The elements ‘A’ and ‘B’ combine together to give two compounds A 2 B 3 and A B 2 . The weight of 0.2 mole of A 2 B 3 is 26g. The weight of 0.3 mole of A B 2 is 24g Then the atomic weights of A and B respectively

# The elements ‘A’ and ‘B’ combine together to give two compounds ${A}_{\text{2}}{B}_{\text{3}}$ and $A{B}_{\text{2}}$. The weight of 0.2 mole of ${A}_{2}{B}_{\text{3}}$ is 26g. The weight of 0.3 mole of $A{B}_{\text{2}}$ is 24g Then the atomic weights of A and B respectively

1. A
15, 20
2. B
20, 25
3. C
20, 30
4. D
25, 30

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### Solution:

Given,

The Weight of 0.2 mole of of ${A}_{2}{B}_{3}$ is 26 g

The weight of 0.3 mole of $A{B}_{\text{2}}$ is 24g

Atomic weight of A and B = ?

Weight of 0.2 mole of ${A}_{\text{2}}{B}_{\text{3}}\to 26\text{\hspace{0.17em}g}$

Weight of one mole® ?

$\frac{1×26}{0.2}=130\text{\hspace{0.17em}g}$

Weight of 0.3 mole of $A{B}_{\text{2}}\to 24\text{\hspace{0.17em}g}$

Weight of 1 mole of A ®?

$\frac{1×24}{0.3}=80\text{\hspace{0.17em}g}$

$2A+3B\to 130........\left(1\right)$

$A+2B\to 80..........\left(2\right)$

On Solving:

$2A+4B\to 160$

$2A+3B\to 130$

$⇒A+2B=80$

$⇒A+2\left(30\right)=80$

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