Equal moles of CO, B 2 H 6 ,    H 2    and    CH 4 are placed in a container. If a hole was made in container after 5 minute, partial pressure of gases in container would be (Atomic weights of C, O, B and H are 12, 16, 11, 1 respectively)

# Equal moles of CO, ${\mathrm{B}}_{2}{\mathrm{H}}_{6},\text{\hspace{0.17em}\hspace{0.17em}}{\mathrm{H}}_{2}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{and}\text{\hspace{0.17em}\hspace{0.17em}}{\mathrm{CH}}_{4}$ are placed in a container. If a hole was made in container after 5 minute, partial pressure of gases in container would be(Atomic weights of C, O, B and H are 12, 16, 11, 1 respectively)

1. A
PCO > PB2H6  >PH2 > PCH4
2. B
PCO = PB2H6  > PCH4> PH2
3. C
PCO > PB2H6  = PH2> PCH4
4. D
PB2H6 >  PH2>PCH4> PCO

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### Solution:

$\mathrm{CO}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{and}\text{\hspace{0.17em}}{\mathrm{B}}_{2}{\mathrm{H}}_{6}$ have same molecular mass. The diffusion of lighter gas will be more. Thus moles coming out from container will show.

${\mathrm{H}}_{2}\text{\hspace{0.17em}}>\text{\hspace{0.17em}\hspace{0.17em}}{\mathrm{CH}}_{4}\text{\hspace{0.17em}\hspace{0.17em}}>\text{\hspace{0.17em}}\mathrm{CO}\text{\hspace{0.17em}\hspace{0.17em}}={\mathrm{B}}_{2}{\mathrm{H}}_{6}.$

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