ChemistryEquivalent Weight of dil.HNO 3 when it reacts with Zn is (At.wt of Zn = 65)

Equivalent Weight of dil.HNO3 when it reacts with Zn is (At.wt of Zn = 65)

  1. A
    65
  2. B
  3. C
  4. D

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    Solution:

    4Zn+10 HNO3(dil.)4Zn(NO3)2+5H2O+N2O

    HNO3 in this reaction acts like both acid and Oxidant

    E.W of HNO3 as an acid. It forms Zn(NO3)2

    No.of replaceable H-atoms in HNO3 = 1

    E.W of HNO3 (acid) = M/1 =M

    E.W of HNO3 as an Oxidant

                                    

    mathop Nlimits^{ + 5} O_3^ - to mathop {{N_2}}limits^{ + 1} O

    decrease in Ox. state =4

    E.W of HNO3 (oxidant) = M/4

    therefore Over all ;EW; of; HNO3 =frac{M}{1}+frac{M}{4}=frac{5M}{4}

                                                          

    =frac{5(65)}{4}
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