ChemistryThe equivalent weight of a metal, 6 g of which evolve 5 .6 L of H 2 at NTP from an acid is:

The equivalent weight of a metal, 6 g of which evolve 5.6L of H2 at NTP from an acid is:

  1. A
    6
  2. B
    12
  3. C
    24
  4. D
    2.4

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    Solution:

    Wt. of metal = 6.0 g;

    volume at NTP = 5.6 L.

    We know that:

    Eq. wt. of a metal = wt. of metal VNTP of H2 in L×11.2L

        Eq. wt. of metal =6.0g5.6L×11.2L=12.0g Ans.

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