Questions  

Following limiting molar conductivities are given as

λmH2SO4=x Scm2mol1 λmK2SO4=y Scm2mol1 λmCH3COOK=z Scm2mol1 λm (in Scm2mol1 ) for CH3COOH willbe 

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a
(xy)2+z
b
xy+2z
c
x+y-z
d
xy+z

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detailed solution

Correct option is A

According to Kohlrausch's law

λmo(AB)=λmoA++λmoB

 So, λmoCH3COOH=λmCH3COO+λmoH+

 So λmoCH3COOH

=λmoCH3COOK+12λmoH2SO412λmK2SO4

=z+x2y2=z+xy2

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