For 2s orbital, the nodal surface exists at the distance

For 2s orbital, the nodal surface exists at the distance

A
$a_{0}$ from the nucleus
B
$1.5 a_{0}$ from the nucleus
C
$2 a_{0}$ from the nucleus
D
infinity from the nucleus

Solution:

At $r = 2 a_{0}$ , there is a node as the value of function $R_{2, 0}$ is zero at this distance

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