For a first order reaction, a plot of log (a-x) against time is a straight line with a negative slope equal to

For a first order reaction, a plot of log (a-x) against time is a straight line with a negative slope equal to

A
$\frac{- k}{2 .303}$
B
- 2.303 k
C
$- \frac{2 .303}{k}$
D
$− \frac{E_{a}}{2 .303 R}$

Solution:

$t = \frac{2 .303}{k} \log \frac{a}{a - x}$

or $t = \frac{2 .303}{k} \log a - \frac{2 .303}{k} \log (a - x)$

slope $= \frac{- 2 .303}{k}$

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