For a gaseous reaction, following data is given:
AB,k1=1015e2000/T CD,k2=1014e1000/T
The temperature at which k1=k2 is :

  1. A

    1000 K

  2. B

    2000 K

  3. C

    868.82K

  4. D

    434.2K

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    Solution:

    When k1=k2
    1015e2000/T=1014e1000/T 10=e1000/T 2.303log10=1000T T=10002.303=434.2K

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