For the following reaction, the mass of water produced from 445g of C57H110O6 is

2C57H110O6(s)+163O2(g)114CO2(g)+110H2O(l)

  1. A

    495 g

  2. B

    490 g

  3. C

    890 g

  4. D

    445 g

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    Solution:

    Moles of C57H110O6(s)=445890=0.5 moles 

    2C57H10O6(s)+163O2(g)114CO2(g)+110H2O(l)nH2O=1104=552mH2O=552×18=495g

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