For the reaction,CO(g)+12O2( g)⇌CO2( g),Kp/KC is - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

The equation for the link between $K_{P}$ and $K_{C}$ is $K_{P} = K_{C} {(RT)}^{∆ n}$

${CO}_{(g)} + \frac{1}{2} O_{2 (g)} ⇌ {CO}_{2 (g)}$

$∆ n = 1 - (1 + 1 / 2)$

$∆ n = 1 - (3 / 2) ∆ n = - 1 / 2$

$K_{P} = K_{C} {(RT)}^{- 1 / 2}$

$\frac{K_{P}}{K_{C}} = {(RT)}^{- 1 / 2}$

For the reaction, ${CO}_{(g)} + \frac{1}{2} O_{2 (g)} ⇌ {CO}_{2 (g)}, K_{p} / K_{C}$ is