Given are the nickel compounds NiCO4, K2NiF6 and K2Ni(CN)4 The order of compounds having increasing oxidation number of nickel is

A
$Ni (CO)_{4} < K_{2} [{NiF}_{6}] < K_{2} [Ni (CN)_{4}]$
B
$Ni (CO)_{4} < K_{2} [Ni (CN)_{4}] < K_{2} [{NiF}_{6}]$
C
$K_{2} [Ni (CN)_{6}] < K_{2} [{NiF}_{6}] < Ni (CO)_{4}$
D
$K_{2} [Ni (CN)_{6}] < Ni (CO)_{4} < K_{2} [{NiF}_{6}]$

Solution:

The oxidation number of nickel in $Ni (CO)_{4}, K_{2} [Ni (CN)_{4}]$ and $K_{2} [{NiF}_{6}]$ are 0, +2 and +4, respectively.

The total number of electrons that an atom acquires or loses in the process of joining with another atom to create a chemical bond is known as the oxidation number, also known as the oxidation state.

Given are the nickel compounds $Ni ({CO}_{4}), K_{2} [{NiF}_{6}]$ and $K_{2} [Ni (CN)_{4}]$ The order of compounds having increasing oxidation number of nickel is

Solution:

Related content