Chemistry9.2 grams of N 2 O 4 ( g ) is taken in a closed one liter vessel and heated till the following equilibrium is reached N 2 O 4 ( g ) ⇋ 2 NO 2 ( g ) . At equilibrium, 50% N 2 O 4 ( g ) is dissociated. What is the equilibrium constant (in mol liter – 1 ) (Molecular weight of N 2 O 4 = 92) ?

9.2 grams of N2O4(g) is taken in a closed one liter vessel and heated till the following equilibrium is reached 

N2O4(g)    2NO2(g).

At equilibrium, 50% N2O4(g) is dissociated. What is the equilibrium constant (in mol liter-1) (Molecular weight of N2O4 = 92) ?

  1. A
    0.1
  2. B
    0.4
  3. C
    0.2
  4. D
    2

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    Solution:

              N2O4(g) 2NO2 Initial:  0.1mol        0      n=9.292 equi. : 0.1-x         2x Given, x=0.1×50100=0.05 KC=NO22N2O4=(2x)20.1-x=4 × 0.0520.05=4 × 0.05=0.2

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