ChemistryH 3 AsO 3 + I 2 + H 2 O = H 3 AsO 4 + 2 HI 0.01 equivalent of the mentioned acid will neutralize how many grams of NaOH?

H3AsO3+I2+H2O=H3AsO4+2HI 0.01 equivalent of the mentioned acid will neutralize how many
grams of NaOH?

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    Solution:

    H3As+3O3+I2+H2O=H3As+5O4+2HI  x 2   Equiv. wt. of H3AsO3= Mol. wt. of H3AsO32=1262=63  0.01 equiv. of H3AsO3=0.63gH3AsO3H3AsO3+2NaOH=Na2HasO3+2H2O 126gH3AsO3 reacts with 80g of NaOH 0.63gH3AsO3 reacts with 80126×0.63g of NaOH = 0.4 g of NaOH.   

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