HNO3   oxidizes NH4+ ions to nitrogen and itself gets reduced to NO2.The moles of HNO3 required by 1 mole of NH42SO4  is

# ${\mathrm{HNO}}_{3}$   oxidizes ${\mathrm{NH}}_{4}^{+}$ ions to nitrogen and itself gets reduced to ${\mathrm{NO}}_{2}.$The moles of ${\mathrm{HNO}}_{3}$ required by 1 mole of ${\left({\mathrm{NH}}_{4}\right)}_{2}{\mathrm{SO}}_{4}\mathrm{ }\mathrm{is}$

1. A

4

2. B

5

3. C

6

4. D

2

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### Solution:

$\begin{array}{l}\mathrm{H}\stackrel{+5}{\mathrm{N}}{\mathrm{O}}_{3}\text{\hspace{0.17em}}+\text{\hspace{0.17em}}\stackrel{-3}{\mathrm{N}}{\mathrm{H}}_{4}^{+}\to {\stackrel{0}{\mathrm{N}}}_{2}+\stackrel{+4}{\mathrm{N}}{\mathrm{O}}_{2}\\ \mathrm{V}.\mathrm{F}.\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}{\mathrm{HNO}}_{3}=\left(5-4\right)=1\\ \mathrm{V}.\mathrm{F}.\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}\hspace{0.17em}}{\mathrm{NH}}_{4}^{+}=\left[0-\left(-3\right)\right]=3\\ \mathrm{so}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{molar}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{ratio}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}{\mathrm{HNO}}_{3}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{and}\text{\hspace{0.17em}\hspace{0.17em}}{\mathrm{NH}}_{4}^{+}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}3\text{\hspace{0.17em}}:\text{\hspace{0.17em}}1.\\ 1\text{\hspace{0.17em}}\mathrm{mole}\text{\hspace{0.17em}}{\left({\mathrm{NH}}_{4}\right)}_{2}{\mathrm{SO}}_{4}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{found}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{to}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{contain}\text{\hspace{0.17em}\hspace{0.17em}}2\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{mole}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}{\mathrm{NH}}_{4}^{+}\\ \mathrm{So},\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{required}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{moles}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}\hspace{0.17em}}{\mathrm{HNO}}_{3}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}\hspace{0.17em}}3\text{\hspace{0.17em}}×\text{\hspace{0.17em}\hspace{0.17em}}2=6\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{moles}.\end{array}$

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