How many moles of PCl5 has to be taken in one litre to get 0.1 mole of chlorine  at equilibrium ? The equilibrium constant Kc of 
PCl5 (g) PCl3 (g) +Cl2 (g) is 0.0414

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    Solution:

    PCl5 (g)  PCl3 (g) + Cl2 (g) 
     x                    0                 0              initially
    (x -a)               a                 a              at equilibrium
    But [Cl2 ]     =    0.1 mol L-1
    So [PCl3] = 0.1 mol L-1 
    and [PCl5 ] = (x-0.1) mol L-1
    and  K = 0.0414
    Since Kc = [PCl3] [Cl2] [PCl5] 
    0.0414x-0.00414 = 0.01 
    0.0414 x= 0.01414
    x =0.014140.0414 = 0.3415  moles

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