Hydrogen can be prepared by the action of dil. H2SO4 on

A
Copper
B
Iron
C
Lead
D
Mercury

Solution:

Hydrogen cannot be prepared by the action of dil. $H_{2} {SO}_{4}$ on copper or mercury as these two metals can not displace hydrogen from acids. Action of dil. $H_{2} {SO}_{4}$ on $Pb$ stops after sometime due to the formation of insoluble ${PbSO}_{4}$ .

Only iron reacts rapidly with dil. $H_{2} {SO}_{4}$ to give $H_{2}$ .

Hydrogen can be prepared by the action of dil. $H_{2} {SO}_{4}$ on

Solution:

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