UncategorizedIf 10 g of Ag reacts with 1 g of sulphur, the amount of Ag2S formed will be [Atomic weight of Ag = 108, S = 32] ?

If 10 g of Ag reacts with 1 g of sulphur, the amount of Ag2S formed will be [Atomic weight of Ag = 108, S = 32] ?

  1. A

    7.75 g

  2. B

    0.775 g

  3. C

    11g

  4. D

    10g

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    Solution:

     Explanation :  

    2  Ag+  S    Ag2S2  ×  108  g  ofAgreactswith32  gofsulphur10g  ofAg  reacts  with32216×  10=320216>1g

    It means ‘S’ is limiting reagent

    32 g of S reacts to form 216 + 32 = 248 g of Ag2S

    1 g of S reacts to form 24832=7.75  g

    Alternative method : 

     neqofAg=10108=0.0925;

    neqofS=116=0.0625neq  =number  of  equivalentsSince  neqofSis  less than neqofAg  0.0625eqofAgwill  react  with  0.0625  eq  of  Sto  form0.0625  eq  ofAg2SHence,  amountofAg2S  =  neq×  Eq.  wt.  of  Ag2S=0.0626  ×  124=7.75g

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