If 10 g of V2O5 is dissolved in acid and is reduced to V2+ by zinc metal, how mole I2 could be reduced by the resulting solution if it is further oxidised to VO2+ ions ?[Assume no change in state of Zn2+ ions] (V = 51, O = 16, I = 127):

If 10 g of V2O5 is dissolved in acid and is reduced to V2+ by zinc metal, how mole I2 could be reduced by the resulting solution if it is further oxidised to VO2+ ions ?

[Assume no change in state of Zn2+ ions] (V = 51, O = 16, I = 127):

  1. A

    0.11 mole of I2

  2. B

    0.22 mole of I2

  3. C

    0.055 mole of I2

  4. D

    0.44 mole of I2

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    Solution:

    Mole of V2O5 = 1051 × 2 + 5 × 16 = 10102 + 80                       = 10182 =.055 Mole of V+2 = .055 × 2   = .1098 mole  0.11 V+2  V+4O+2  + 2e-   Moles  of I2 = Moles of V+2 = .11

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