If an aqueous solution at 250c  has twice as many OH- as pure water ,its pOH will be

If an aqueous solution at 250c  has twice as many OH- as pure water ,its pOH will be

  1. A

    6.699

  2. B

    7.307

  3. C

    7

  4. D

    6.98

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    Solution:

     [OH-] of pure water = 1×1O-7

    OH- given solution =  2 × 10-7

    pOH=-logOH-=-log2×10-7 =7-log2=7-0.3010=6.990 

     

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