If an electron jump from 3rd orbit to 2nd orbit in Li2+ then calculate change in energy of electron will be:

If an electron jump from 3rd orbit to 2nd orbit in Li²⁺ then calculate change in energy of electron will be:

A
5.4eV
B
17eV
C
1.8eV
D
15eV

Solution:

$\begin{array}{l} ΔE = 13 .6 \times 9 (\frac{1}{2^{2}} - \frac{1}{3^{2}}) \\ = 13 .6 \times 9 \times \frac{5}{4 \times 9} = 17 eV \end{array}$

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