ChemistryIf bond dissociation energies of N≡N, H-H, and N-H are x1, x2 and x3 respectively, hence enthalpy of formation of NH3(g) is

If bond dissociation energies of NN, H-H, and N-H are x1, x2 and x3 respectively, hence enthalpy of formation of NH3(g) is

  1. A

    x1+3x26x3

  2. B

    3x312x132x2

  3. C

    x12+32x23x3

  4. D

    6x3x13x2

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    Solution:

    12N2(g)+32H2(g)NH3(g)ΔrH=ΔformHNH3,gΔformHNH3,g=12DNN+32DHH3DNH=12×x1+32x23x3

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