Search for: If IE and EA of an element are 280 and 90 Kcal mol-1 respectively then EN of the element on Pauling scale is: If IE and EA of an element are 280 and 90 Kcal mol-1 respectively then EN of the element on Pauling scale is: A2.96B2.6C0D4.0 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution: When IE & EA are taken in Kcal mol-1,EN=IE+EA125=280+90125=2.96 Related content Leave Application For Teacher What is Surface Tension – Dimensions, Derivations, Causes and Examples Odisha Traditional Dress Official Leave Application Format, Samples NEET Physics Syllabus 2024, Deleted and Updates Topics from NCERT, Best Books for Physics Indian History, Culture, and Diversity Leave Application Mail Application For Leave For Teacher Anthropological Survey of India CBSE Class 12 Hindi Syllabus 2023-24