If IE and EA of an element are 280 and 90 Kcal mol-1 respectively then EN of the element on Pauling scale is:

If IE and EA of an element are 280 and 90 Kcal mol-1 respectively then EN of the element on Pauling scale is:

  1. A

    2.96

  2. B

    2.6

  3. C

    0

  4. D

    4.0

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    Solution:

     When IE & EA are taken in Kcal mol-1,

    EN=IE+EA125=280+90125=2.96

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