If n = 6, the correct sequence for filling of electrons will be

If n = 6, the correct sequence for filling of electrons will be

A
$ns \to (n - 2) f \to (n - 1) d \to np$
B
$ns \to (n - 1) d \to (n - 2) f \to np$
C
$ns \to (n - 2) f \to np \to (n - 1) d$
D
$ns \to np (n - 1) d \to (n - 2) f$

Solution:

$ns \to (n - 2) f \to (n - 1) d \to np [n = 6]$

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