If the total equilibrium pressure of NH4HS(s)⇌NH3(g)+H2S(g) is 4 atm, the equilibrium constant is :

If the total equilibrium pressure of ${NH}_{4} HS (s) ⇌ {NH}_{3} (g) + H_{2} S (g)$ is 4 atm, the equilibrium constant is :

$N H_{4} S H (s) ⇌ N H_{3} (g) + H_{2} S (g)$

p p (at equilibrium)

Total pressure at equilibrium = p+ p

4 = 2p or p = 2

$K_{p} = p_{N H_{3}} \times p_{H_{2} S}$ $= 2 \times 2 = 4 a t m^{2}$

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