If the total equilibrium pressure of NH4HS(s)NH3(g)+H2S(g)  is 4 atm, the equilibrium constant is :

  1. A

    4 atm

  2. B

    2 atm

  3. C

    4 atm2

  4. D

    2 atm2

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    Solution:

    NH4SH(s)NH3(g)+H2S(g)

                                 p                       p (at equilibrium)

    Total pressure at equilibrium = p+ p

    4 = 2p       or            p  = 2

    Kp=pNH3×pH2S =2×2=4  atm2

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