# Imagine a universe in which :(a) Principal quantum no, n can have values from 1,2,3,....$\infty$(b) Azimuthal quantum no. l can have values from 1 to n + 1 corresponding to $\mathrm{A},\mathrm{B},\mathrm{C},\mathrm{D},\mathrm{E},\mathrm{F}$....(c) Magnetic quantum no. m can have integral values from $-\frac{1}{2}$ to $-\frac{1}{2}$ (including zero if possible).(d) Spin quantum no. 8 can have 6 possible values.All rules of filling remains intact.What will be the atomic no. of the element in which last ${e}^{-}$ fills the 2nd shell completely

1. A

38

2. B

57

3. C

76

4. D

96

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### Solution:

The order of shell,

$=96$

The atomic no. of the element in last ${e}^{-}$ fills the 2nd shell completely is 96.

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