Imagine a universe in which :
(a) Principal quantum no, n can have values from 1,2,3,....
(b) Azimuthal quantum no. l can have values from 1 to n + 1 corresponding to A,B,C,D,E,F....
(c) Magnetic quantum no. m can have integral values from 12 to 12 (including zero if possible).
(d) Spin quantum no. 8 can have 6 possible values.
All rules of filling remains intact.

What will be the atomic no. of the element in which last e fills the 2nd shell completely

  1. A

    38

  2. B

    57

  3. C

    76

  4. D

    96

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    Solution:

    The order of shell,

    1A<1B<2A<2B<3A<2C<3B<4A12 18 12 18 12 24   18

    =96

    The atomic no. of the element in last e fills the 2nd shell completely is 96.

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