In a cubic arrangement of atoms of A, B and C, atoms of A are present at the corners of the unit cell,B atoms are at face centers and C at tetrahedral voids. If one of the atom from one corner is missing in the unit cell, then the simplest formula of compound will be:

  1. A

    A7B3C8

  2. B

    A7B24C64

  3. C

    A718B3C4

  4. D

    A7B48C64

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    Solution:

    Number of atoms of A in unit cell=7×18=78

    Number of atoms of B in unit cell=6×12=3

    Number of atoms of C in unit cell=8×1=8

    Simplest formula=A7/8B3C8

                                    =A7B24C64

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