In a reaction A→B when the concentration of reactant is made 8 times,the rate got doubled. The order of reaction is

In a reaction A→B when the concentration of reactant is made 8 times,the rate got doubled. The order of reaction is

A
1/3
B
1
C
1/2
D
2

Solution:

$\frac{2 r}{r} = \frac{k {[8 A]}^{x}}{k {[A]}^{x}}$

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