In an electrochemical cell ΔG=ΔH

# In an electrochemical cell $\mathrm{\Delta G}=\mathrm{\Delta H}$

1. A

T→0

2. B

T→∞

3. C

4. D

Both (a) and (c)

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### Solution:

$\begin{array}{l}\mathrm{\Delta G}=\mathrm{\Delta H}-\mathrm{T}{\left(\frac{\mathrm{d}\left(\mathrm{\Delta G}\right)}{\mathrm{dT}}\right)}_{\mathrm{p}}\\ \mathrm{\Delta G}=\mathrm{\Delta H}+\mathrm{nFT}{\left(\frac{\mathrm{dE}}{\mathrm{dT}}\right)}_{\mathrm{p}}\end{array}$
as T → 0 $\mathrm{\Delta G}=\mathrm{\Delta H}$ and when ${\left(\frac{\mathrm{dE}}{\mathrm{dT}}\right)}_{\mathrm{p}}=0,\mathrm{\Delta G}=\mathrm{\Delta H}$

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