In an organic compound of molar mass 108 gm mol 1 C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular formula can be : - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
$C_{6} H_{8} N_{2}$
B
$C_{7} H_{10} N$
C
$C_{5} H_{6} N_{3}$
D
$C_{4} H_{18} N_{3}$

Solution:

Mole $\begin{array}{ccc} C & H & N \\ \frac{9}{12} & \frac{1}{1} & \frac{3 .5}{14} \\ \frac{3}{4} & : 1 & : \frac{1}{4} \\ 3 & : 4 & : 1 \end{array}$
$n = \frac{108}{54} = 2$
$\begin{array}{l} \Rightarrow C_{3} H_{4} N \Rightarrow M . F = {(C_{3} H_{4} N)}_{n} \\ MF = {(C_{3} H_{4} N)}_{2} = C_{6} H_{8} N_{2} \end{array}$

Solution:

Related content