In an organic compound of molar mass 108 gm mol 1 C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular formula can be :

# In an organic compound of molar mass 108 gm mol 1 C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular formula can be :

1. A

${\mathrm{C}}_{6}{\mathrm{H}}_{8}{\mathrm{N}}_{2}$

2. B

${\mathrm{C}}_{7}{\mathrm{H}}_{10}\mathrm{N}$

3. C

${\mathrm{C}}_{5}{\mathrm{H}}_{6}{\mathrm{N}}_{3}$

4. D

${\mathrm{C}}_{4}{\mathrm{H}}_{18}{\mathrm{N}}_{3}$

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### Solution:

Mole $\begin{array}{ccc}\mathrm{C}& \mathrm{H}& \mathrm{N}\\ \frac{9}{12}& \frac{1}{1}& \frac{3.5}{14}\\ \frac{3}{4}& :1& :\frac{1}{4}\\ 3& :4& :1\end{array}$
$\mathrm{n}=\frac{108}{54}=2$
$\begin{array}{l}⇒{\mathrm{C}}_{3}{\mathrm{H}}_{4}\mathrm{N}⇒\mathrm{M}.\mathrm{F}={\left({\mathrm{C}}_{3}{\mathrm{H}}_{4}\mathrm{N}\right)}_{\mathrm{n}}\\ \mathrm{MF}={\left({\mathrm{C}}_{3}{\mathrm{H}}_{4}\mathrm{N}\right)}_{2}={\mathrm{C}}_{6}{\mathrm{H}}_{8}{\mathrm{N}}_{2}\end{array}$

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