In order to cause coagulation of 100 ml Arsenious sulphide sol 111.7 mg of 2 m NaCl solution is used what will be the flocculation value of NaCl?

In order to cause coagulation of $100 m l$ Arsenious sulphide sol $111.7 m g$ of $2 m$ $N a C l$ solution is used what will be the flocculation value of $N a C l$ ?

Millimole of $N a C l$ for $1$ litre $= \frac{2}{1117} x 10 x 1117 = 2$

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