In order to coagulate 400 ml of Fe(OH)3 sol completely 60 ml of 0.1M KCl is required. What will be the coagulation power of KCl?

In order to coagulate $400 ml$ of $Fe {(OH)}_{3}$ sol completely $60 ml$ of $0.1 M KCl$ is required. What will be the coagulation power of $KCl$ ?

For $400 ml Fe {(OH)}_{3} mm$ of $KCl required = 6$

For $1000 ml Fe {(OH)}_{3} mm$ of $KCl required = \frac{6}{400} \times 1000 = 15$

Coagulator power $= \frac{1}{15}$

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