In the balanced chemical reaction,IO3- + aI- + bH+ →  CH2O + dI2a, b, c and d respectively correspond to

In the balanced chemical reaction,

IO3- + aI- + bH+   CH2O + dI2

a, b, c and d respectively correspond to

  1. A

    5, 6, 5, 5

  2. B

    5, 3, 6, 3

  3. C

    3, 5, 3, 6

  4. D

    5, 6, 3, 3

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    Solution:

    IO3- + aI- + bH+   CH2O + dI2

    OxidationReduction

    I-1   I2 oxidation

    2I-1   I2 

    2I-1   I2 +2e----(1)

    IO3-   I2 reduction

    2IO3-I2

    2IO3- + 12H+  I2 + 6H2O

    2IO3- + 12H+ +10e-  I2 + 6H2O ---(2)

            (2)  2IO3-+10e-+12H+ I2 + 6H2O (1)×5                        10I- 5I2 +10e-                

     On addition: 2IO3-+10I-+12H+ 6I2 + 6H2O

                            IO3-+5I-+6H+3I2+3H2O

    On comparing, a = 5, b = 6, c = 3, d = 3

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