In the calculation of wave number of an electronic transition using Rydberg's equation, sum of n1 and n2 is maximum for - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
First line of Pfund series
B
Second line of Brackett series
C
Third line of Lyman series
D
Fourth line of Paschen series

Solution:

$\bar{ν} = \frac{1}{λ} = R_{H} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]; (1) n_{1} + n_{2} = 5 + 6 (2) n_{1} + n_{2} = 4 + 6 (3) n_{1} + n_{2} = 1 + 4 (4) n_{1} + n_{2} = 3 + 7$

In the calculation of wave number of an electronic transition using Rydberg's equation, sum of n₁ and n₂ is maximum for

Solution:

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