In the following reaction.   RCH2CH=CH2+ICl[A], Markonikoffs product [A] is  

  1. A

    RCH2CHCH2l              ι            Cl

  2. B

    RCH2CHCH2Cl                  ι                  I

  3. C

    RCHCH=CH2                ι               Cl

  4. D

    RCH=CHCH2I

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    Solution:

    Markownikoffs addition The negative part of the un-svmrnetrical reagent adds to a less hydrogenated (more substituted) carbon atom of the> double bond. In IC!. Cl is more electronegative. So. it will take negative charge. 

    I.e   I+Cl 

     So. the product is

    RCH2CH=CH2+lClRRCH2CH(Cl)CH2I                                                                                                                                                    

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