In the following reaction. RCH2CH=CH2+ICl→[A], Markonikoffs product [A] is - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
${RCH}_{2} CH - {CH}_{2} l ι Cl$
B
${RCH}_{2} - CH - {CH}_{2} Cl ι I$
C
$RCH - CH = {CH}_{2} ι Cl$
D
$RCH = CH - {CH}_{2} I$

Solution:

Markownikoffs addition The negative part of the un-svmrnetrical reagent adds to a less hydrogenated (more substituted) carbon atom of the> double bond. In IC!. Cl is more electronegative. So. it will take negative charge.

I.e $I^{+} {Cl}^{-}$

So. the product is

${RCH}_{2} CH = {CH}_{2} + lCl ⟶ R - \to R - {CH}_{2} - CH (Cl) - {CH}_{2} I$

In the following reaction. ${RCH}_{2} CH = {CH}_{2} + ICl \to [A]$ , Markonikoffs product [A] is

Solution:

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