In the reaction : Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H 2O, the oxidation state of lead changes from

In the reaction : Pb₃O₄ + 8HCl → 3PbCl₂ + Cl₂ + 4H ₂O, the oxidation state of lead changes from

A
+2 to zero
B
+2 to +4
C
+4 to +2
D
+4 to zero

Solution:

Pb₃O₄ is a mixed oxide. It exist as PbO₂.2PbO
Pb₃O₄+ 8HCl → 3PbCl₂ + Cl₂ + 4H₂O
This reaction can be split into
A)

large mathop {2PbO}limits^{ + 2} ; + ;4HCl; to ;mathop {2PbC{l_2}}limits^{ + 2} ; + ;2{H_2}O

B)

large mathop {Pb{O_2}}limits^{ + 4} ; + ;4HCl; to ;mathop {PbC{l_2}}limits^{ + 2} ; + ;C{l_2}; + ;2{H_2}O

Oxidation state of Pb changes from +4 to +2

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