In the  reaction 2A+BA2B, if the concertation of A is doubled and that of B is halved, then the rate of the reaction will 

  1. A

    increases 2 times

  2. B

    increases 4 times

  3. C

    decreases 2 times

  4. D

    remain the same

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    Solution:

    2A+BA2B

    r1=k[A]2[B]            .....(i)

    When, [A]=[2A],[B]=[B2]

    r2=k[2A]2[B2]=k4[A]2[B]2

    =k2[A]2[B]=2r1        (r1=k[A]2[B])

     Rate of reaction is increased two times

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