In the reactionC2O42- + MnO4- + H+  →   Mn2+  +  CO2 + H2Othe reductant is

In the reaction

C2O42- + MnO4- + H+     Mn2+  +  CO2 + H2O

the reductant is

  1. A

    C2O42- 

  2. B

    MnO4-

  3. C

    Mn2+  

  4. D

    H+ 

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    Solution:

    C+32O4-2 + Mn+7O4- + H+     Mn2+  +  C+4O2 + H2O ;

    In this reaction  C2O42-   acts as a reducing agent.

    Oxidation state of Carbon changes from +3 to +4 , thus it undergoes oxidation and acts as reducing agent.

    It reduces MnO4- to Mn+2 and thus acts like reducing agent.

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