Kc for N2+O2 = 2NO at certain temp is 1.6 x 10-3, then Kp for NO = 12N2+12 2O2 at same temperature will be: - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

N₂ + O₂⇌ 2NO

K_C=1.6 x 10^-3

$K_{c} = \frac{{[NO]}^{2}}{[NO] [O_{2}]}$ = 1.6 x 10^-3

$\frac{1}{2} N_{2} + \frac{1}{2} O_{2}$

$Kc = \frac{{[N_{2}]}^{\frac{1}{2}} {[O_{2}]}^{\frac{1}{2}}}{[NO]}$

${(\frac{1}{K_{c}})}^{\frac{1}{2}} = {(\frac{1}{1.6 \times 10^{- 3}})}^{\frac{1}{2}}$

K_c= $\frac{10^{2}}{4}$ = 25

K_p= K_c

K_p=25

Therefore, the correct answer is 25.

K_c for N₂+O₂= 2NO at certain temp is 1.6 x 10^-3, then K_p for NO = $\frac{1}{2}$ N₂+ $\frac{1}{2}$ 2O₂ at same temperature will be: