Kc for N2+O2 = 2NO at certain temp is 1.6 x 10-3, then Kp for NO = 12N2+12 2O2 at same temperature will be:

# Kc for N2+O2 = 2NO at certain temp is 1.6 x 10-3, then Kp for NO = $\frac{1}{2}$N2+$\frac{1}{2}$ 2O2 at same temperature will be:

1. A

25

2. B

25 atm

3. C

5 atm

4. D

1.6 x 10-3atm-1

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### Solution:

N2 + O2 ⇌ 2NO

KC=1.6 x 10-3

${\mathrm{K}}_{\mathrm{c}}=\frac{{\left[\mathrm{NO}\right]}^{2}}{\left[\mathrm{NO}\right]\left[{\mathrm{O}}_{2}\right]}$= 1.6 x 10-3

${\left(\frac{1}{{\mathrm{K}}_{\mathrm{c}}}\right)}^{\frac{1}{2}}={\left(\frac{1}{1.6×{10}^{-3}}\right)}^{\frac{1}{2}}$

Kc $\frac{{10}^{2}}{4}$ = 25

Kp = Kc

Kp=25

Therefore, the correct answer is 25.

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