Mass of a particle ‘A’ is 1.656 X 10-16 Kg. Magnitude of velocity of ‘A’ is equal to its Debroglie wavelength. Debroglie wavelength of ‘A’ will be

Mass of a particle ‘A’ is 1.656 X 10-16 Kg. Magnitude of velocity of ‘A’ is equal to its Debroglie wavelength. Debroglie wavelength of ‘A’ will be

  1. A

    0.2 A0

  2. B

    200 A0

  3. C

    20 A0

  4. D

    2 A0

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    Solution:

    λ=hmv;Given   λ=v;λ2=hmλ=hmλ=6.625×1034J.s1.656×1016Kgλ=2×109mλ=20 A0

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