# Maximum value of $n+l+m$ for the last unpaired electron in an element present in 17th group and 4th period of periodic table:

1. A

4

2. B

5

3. C

6

4. D

7

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### Solution:

For 17th group and 4th period of periodic table the value of the principal(n),azimuthal(l) and magnetic quantum number (m) is 4,1 and +1.

$n=4$

$l=1$

$m=+1$

The maximum value of $n+l+m$ for the last unpaired electron in an element is found by the calculation,

Hence he maximum value of $n+l+m$ is 6.

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