Number of protons, neutrons and electrons in the nuclide X 54135 are P, Q, R respectively. P, Q, R respectively are

Number of protons, neutrons and electrons in the nuclide ${}_{54}^{135}X$ are P, Q, R respectively. P, Q, R respectively are

A
54, 54, 81
B
54, 81, 54
C
81, 54, 54
D
54, 54, 54

Solution:

$Given {}_{Z}^{A}X = {}_{54}^{135}X; Z = 54 = number of protons and electrons; A - Z = 135 - 54 = 81 neutrons$

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