O-O bond order is 2 in the following species - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
$O_{2}$
B
$O_{2}^{+}$
C
$O_{2}^{-}$
D
$O_{2}^{- 2}$

Solution:

$O_{2}^{- 2} - {KK}^{'} {(σ_{2 s})}^{2} {(σ_{2 s}^{*})}^{2} {({σ_{2 p}}_{z})}^{2} {(π_{2 p_{x}})}^{2} {(π_{2 p_{y}})}^{2} {(π_{2 p_{x}}^{*})}^{2} {(π_{2 p_{y}}^{*})}^{2}$

$O_{2}^{-} - {KK}^{'} {(σ_{2 s})}^{2} {(σ \overset{*}{_{2 s}})}^{2} {({σ_{2 p}}_{z})}^{2} {(π_{2 p_{y}})}^{2} {(π_{2 p_{y}})}^{2} {(π_{2 p_{x}}^{*})}^{2} {(π_{2 p_{y}}^{*})}^{1}$

$O_{2}^{} - {KK}^{'} {(σ_{2 s})}^{2} {(σ_{2 s}^{*})}^{2} {({σ_{2 p}}_{z})}^{2} {(π_{2 p_{x}})}^{2} {(π_{2 p_{y}})}^{2} {(π_{2 p_{x}}^{*})}^{1} {(π_{2 p_{y}}^{*})}^{1}$

$O_{2}^{+} - {KK}^{'} {(σ_{2 s})}^{2} {(σ_{2 s}^{*})}^{2} {(σ_{2 p_{z}})}^{2} {(π_{2 p_{x}})}^{2} {(π_{2 p_{y}})}^{2} {(π_{2 p_{x}}^{*})}^{1} {(π_{2 p_{y}}^{*})}^{0}$

Bond order in

$O_{2}^{- 2} = \frac{10 - 8}{2} = 1; O_{2}^{-} = \frac{10 - 7}{2} = 1.5; O_{2} = \frac{10 - 6}{2} = 2; O_{2}^{+} = \frac{10 - 5}{2} = 2.5;$

O $—$ O bond length in

$O_{2}^{- 2} > O_{2}^{-} > O_{2} > O_{2}^{+}$

Solution:

Related content