One mole of an ideal gas is expanded reversibly and isothermally from 10 litres to 100 litres at 1000 K.  Work done during the process is ‘X’ kcals. Value of ‘X’ is

  1. A

    -4.606

  2. B

    -2.303

  3. C

    -4606

  4. D

    -2303

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    Solution:

    Wrev=2.303nRT logVfVi;Wrev=2.303(1 mole)(2 cals.K-1. mol-1)(1000 K) log10010;Wrev=-4.606 ×103 cals =-4.606 kcals ;

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