One mole of an ideal gas is put through a series of changes as shown in the figure in which 1, 2, 3 mark the three stages of the system. Find the Pressure at the three stages.

# One mole of an ideal gas is put through a series of changes as shown in the figure in which 1, 2, 3 mark the three stages of the system. Find the Pressure at the three stages.

1. A

1-107; 2-2.214; 3-1.107

2. B

1-1.113; 2-2.226; 3-2.226

3. C

2-2.214; 2-1.107 3-2.214

4. D

1-1.107; 2-2.214; 3-2.214

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### Solution:

At stage (1)

$\mathrm{V}=22.4\mathrm{L}=22.4×{10}^{-3}{\mathrm{m}}^{3}$

T = 300 K, n = 1 mol.

$\mathrm{p}=\frac{\mathrm{nRT}}{\mathrm{V}}=\frac{1\mathrm{mol}×8.314{\mathrm{Pam}}^{3}{\mathrm{mol}}^{-1}{\mathrm{K}}^{-1}×300\mathrm{K}}{22.4×{10}^{-3}{\mathrm{m}}^{3}}$

- 1.1 13 x l05 Pa = 1.113 bar

At stage (2) temperature is doubled but volume is constant.

At stage (3), T is 300 K and V is 11.2 L and as in stage (1).

$p=\frac{nRT}{V}=2.226\mathrm{bar}$

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