One mole of an ideal gas is put through a series of changes as shown in the figure in which 1, 2, 3 mark the three stages of the system. Find the Pressure at the three stages. 

One mole of an ideal gas is put through a series of changes as shown in the figure in which 1, 2, 3 mark the three stages of the system. Find the Pressure at the three stages.

 

  1. A

    1-107; 2-2.214; 3-1.107

     

  2. B

    1-1.113; 2-2.226; 3-2.226

     

  3. C

    2-2.214; 2-1.107 3-2.214

     

  4. D

    1-1.107; 2-2.214; 3-2.214

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    Solution:

    At stage (1)

    V=22.4L=22.4×103m3

    T = 300 K, n = 1 mol.

    p=nRTV=1mol×8.314Pam3mol1K1×300K22.4×103m3

    - 1.1 13 x l05 Pa = 1.113 bar

    At stage (2) temperature is doubled but volume is constant.

     Thus, PT,=2.226bar

    At stage (3), T is 300 K and V is 11.2 L and as in stage (1).

    p=nRTV=2.226bar

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