One mole of calcium carbonate on thermal decomposition gives ‘X’ grams of residue. ‘X’ on heating with coke gets completely converted to ‘Y’ grams of solid. ‘Y’ grams of this solid on hydrolysis gives 19.5 grams of a gaseous product ‘Z’ . Percentage yeild of ‘Z’ obtained is

One mole of calcium carbonate on thermal decomposition gives ‘X’ grams of residue. ‘X’ on heating with coke gets completely converted to ‘Y’ grams of solid. ‘Y’ grams of this solid on hydrolysis gives 19.5 grams of a gaseous product ‘Z’ . Percentage yeild of ‘Z’ obtained is

  1. A

    80%

  2. B

    60%

  3. C

    90%

  4. D

    75%

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    Solution:

    CaCO3s1  moleCaOs1  mole+CO2gCaOs1  mole56g+3CsCaC2s1  mole64g+COgCaC264gs+2H2OC2H226gg+CaOH2If  the  yield  of  C2H2  is  100%  then  weight   ofC2H2  formed  must  be  26g but only  19.5g  of  C2H2  isformced%yiel  of  product=19.526×100=75%

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