pKa of a weak acid is defined as

${pK}_{a}$ of a weak acid is defined as

A
$\log_{10} K_{a}$
B
$\frac{1}{\log_{10} K_{a}}$
C
$\log_{10} \frac{1}{K_{a}}$
D
$- \log_{10} \frac{1}{K_{c}}$

Solution:

It is defined as

pKa=log₁₀1/K_a

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