Q, P, A, X and E are the elements belonging to 14th group of Modern periodic table. The correct trend of ionization potential for these elements is  Q > P > A > X > E . The element ‘P’ in the sequence is

Q, P, A, X and E are the elements belonging to 14th group of Modern periodic table. The correct trend of ionization potential for these elements is  Q > P > A > X > E . The element ‘P' in the sequence is

  1. A

    Si

  2. B

    Sn

  3. C

    C

  4. D

    Ge

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    Solution:

    Atomic radius trend…C<Si<Ge<Sn<Pb;

    IP1 and M.P trend…C>Si>Ge>Pb>Sn;

    EN trend…C>Pb>Si=Ge=Sn;

    Density…..C(graphite)<Si<C(diamond)<Ge<Sn<Pb;

    B.P trend…C>Si>Ge>Sn>Pb;

    Resistivity…C>Si=Ge>Pb>Sn;

    Conductivity…C<Si=Ge<Pb<Sn

     

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