Radius of third orbit in Be+3 ion is n ×r0. Value of n is equal to (ro= Bohr’s radius = radius of first orbit in H-atom)

Radius of third orbit in ${Be}^{+ 3}$ ion is n $\times$ r₀. Value of n is equal to (r_o= Bohr's radius = radius of first orbit in H-atom)

$r_{n} = \frac{n^{2}}{Z} r_{o}; r_{3} ({Be}^{+ 3}, Z = 4) = \frac{3^{2}}{4} \times r_{0}$

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