The law of triads is applicable to a group of

The law of triads is applicable to a group of

1. A

Cl, Br, I

2. B
C, N, O
3. C
Na, K, Rb
4. D

None of these

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Solution:

Atomic weight of $Cl=35.5$ .

Atomic weight of $\text{Br}=80.0$

Atomic weight of $\text{I}=127$

According to law of triads the arithmetic mean of first and third elements is equal to atomic weight of middle element.

Arithmetic mean of $\text{C}l\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}\text{I}=\frac{35.5+127}{2}$ $=81.25$

So, Cl, Br, I nearly follows law of triads.

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