The activation energy of a reaction at a given temperature is found to be 2.303 RTJ mol-. The ratio of rate constant to the Arrhenius factor is

  1. A

    0.01

  2. B

    0.1

  3. C

    0.02

  4. D

    0.001

    Join Our Infinity Learn's Learning Program!

    FREE Lve Classes, PDFs, Solved Questions, PYQ's, Mock Tests, Practice Tests, and Test Series!

    +91

    Verify OTP Code (required)


    I agree to the terms and conditions and privacy policy.

    Solution:

    Let Ea= activation energy, k is rate constant and A is Arrhenius factor. We know that:

    logkA=Ea2.303RT;logkA=2.300RT2.303RT=1

    kA= antilog (1) or kA=0.1.

    Chat on WhatsApp

      Join Infinity Learn Regular Class Program!

      Sign up & Get instant access to FREE PDF's, solved questions, Previous Year Papers, Quizzes and Puzzles!

      +91

      Verify OTP Code (required)





      I agree to the terms and conditions and privacy policy.